Lines Matching +full:high +full:- +full:bit

1 /* SPDX-License-Identifier: GPL-2.0 */
19  *    by subtracting 0x01010101, and seeing if any of the high bits of each
22  *    significant), so it is 0x00 - 0x01 == 0xff. For all other
23  *    byte values, either they have the high bit set initially, or when
24  *    1 is subtracted you get a value in the range 0x00-0x7f, none of which
25  *    have their high bit set. The expression here is
26  *    (x - 0x01010101) & ~x & 0x80808080), which gives 0x00000000 when
29  *    byte to a true match due to carries.  For little-endian this is
31  *    we're interested in, but big-endian needs method 2 to find which
34  *    calculating ~(((x & ~0x80808080) - 0x80808080 - 1) | x | ~0x80808080).
37  *    byte, and the '| x' part ensures that bytes with the high bit set
38  *    produce 0x00. The addition will carry into the high bit of each byte
40  *    which was the most significant bit set and divide by 8 to find how
49 	addi	r10, r3, -4
52 	bne-	3f