Lines Matching +full:5 +full:k

48 __attribute__((nonnull(2,3,4,5)))
134  * 2:1 balanced merges.  Given two pending sublists of size 2^k, they are
135  * merged to a size-2^(k+1) list as soon as we have 2^k following elements.
137  * Thus, it will avoid cache thrashing as long as 3*2^k elements can
146  * Each time we increment "count", we set one bit (bit k) and clear
147  * bits k-1 .. 0.  Each time this happens (except the very first time
148  * for each bit, when count increments to 2^k), we merge two lists of
149  * size 2^k into one list of size 2^(k+1).
152  * 2^k, which is when we have 2^k elements pending in smaller lists,
153  * so it's safe to merge away two lists of size 2^k.
155  * After this happens twice, we have created two lists of size 2^(k+1),
156  * which will be merged into a list of size 2^(k+2) before we create
157  * a third list of size 2^(k+1), so there are never more than two pending.
159  * The number of pending lists of size 2^k is determined by the
160  * state of bit k of "count" plus two extra pieces of information:
162  * - The state of bit k-1 (when k == 0, consider bit -1 always set), and
164  *   is count >= 2^(k+1)).
168  * 0:  00x: 0 pending of size 2^k;           x pending of sizes < 2^k
169  * 1:  01x: 0 pending of size 2^k; 2^(k-1) + x pending of sizes < 2^k
170  * 2: x10x: 0 pending of size 2^k; 2^k     + x pending of sizes < 2^k
171  * 3: x11x: 1 pending of size 2^k; 2^(k-1) + x pending of sizes < 2^k
172  * 4: y00x: 1 pending of size 2^k; 2^k     + x pending of sizes < 2^k
173  * 5: y01x: 2 pending of size 2^k; 2^(k-1) + x pending of sizes < 2^k
176  * We gain lists of size 2^k in the 2->3 and 4->5 transitions (because
177  * bit k-1 is set while the more significant bits are non-zero) and
178  * merge them away in the 5->2 transition.  Note in particular that just
179  * before the 5->2 transition, all lower-order bits are 11 (state 3),
184  * 5 above, you can see that the number of elements we merge with a list
185  * of size 2^k varies from 2^(k-1) (cases 3 and 5 when x == 0) to
186  * 2^(k+1) - 1 (second merge of case 5 when x == 2^(k-1) - 1).