Lines Matching refs:ancestors

302 	return sch->ancestors[ancestor->level] == ancestor;
330 	 * bypassing sub-trees. If all ancestors including root are bypassing,
3543 			struct scx_sched *anc = sch_a->ancestors[level];
3545 			if (anc == sch_b->ancestors[level] &&
6240 	 * if itself or any of its ancestors are in bypass mode. A descendant's
6241 	 * depth is the sum of its own bypasses and its ancestors', so every
7303 	sch = kzalloc_flex(*sch, ancestors, level + 1);
7378 		memcpy(sch->ancestors, parent->ancestors,
7379 		       level * sizeof(parent->ancestors[0]));
7380 	sch->ancestors[level] = sch;
7594 	    !(sch->ancestors[0]->ops.flags & SCX_OPS_TID_TO_TASK)) {