1 /* 2 * CDDL HEADER START 3 * 4 * The contents of this file are subject to the terms of the 5 * Common Development and Distribution License (the "License"). 6 * You may not use this file except in compliance with the License. 7 * 8 * You can obtain a copy of the license at usr/src/OPENSOLARIS.LICENSE 9 * or http://www.opensolaris.org/os/licensing. 10 * See the License for the specific language governing permissions 11 * and limitations under the License. 12 * 13 * When distributing Covered Code, include this CDDL HEADER in each 14 * file and include the License file at usr/src/OPENSOLARIS.LICENSE. 15 * If applicable, add the following below this CDDL HEADER, with the 16 * fields enclosed by brackets "[]" replaced with your own identifying 17 * information: Portions Copyright [yyyy] [name of copyright owner] 18 * 19 * CDDL HEADER END 20 */ 21 /* 22 * Copyright 2007 Sun Microsystems, Inc. 23 * All rights reserved. 24 * Use is subject to license terms. 25 * 26 * Very crude pig latin converter. 27 * Piglatin is an encoded form of English that is often used by children 28 * as a game. A piglatin word is formed from an English word by: 29 * 30 * . If the word begins with a consonant, move the consonant to the end of 31 * the word and append the letters "ay". Example: "door" becomes "oorday". 32 * 33 * . If the word begins with a vowel, merely append "way" to the word. 34 * Example: "ate" becomes "ateway 35 */ 36 37 #include <stdio.h> 38 #include <strings.h> 39 #include <ctype.h> 40 41 int 42 main() 43 { 44 char buffer[32767], * cb, * sb; 45 int ic, ignore = 0, word = 0; 46 47 sb = cb = &buffer[0]; 48 *sb = '\0'; 49 50 while ((ic = getc(stdin)) != EOF) { 51 char c = (char)ic; 52 53 /* 54 * Ignore all possible formatting statements. 55 */ 56 if (c == '%') 57 ignore = 1; 58 59 /* 60 * Isolate the word that will be converted. 61 */ 62 if (isspace(ic) || (ispunct(ic) && ((ignore == 0) || 63 ((c != '%') && (c != '.') && (c != '#') && (c != '-'))))) { 64 char s = buffer[0]; 65 66 /* 67 * If we haven't collected any words yet simply 68 * printf the last character. 69 */ 70 if (word == 0) { 71 (void) putc(ic, stdout); 72 continue; 73 } 74 75 /* 76 * Leave format strings alone - contain "%". 77 * Leave single characters alone, typically 78 * these result from "\n", "\t" etc. 79 */ 80 if ((ignore == 0) && ((cb - buffer) > 1)) { 81 if ((s == 'a') || (s == 'A') || 82 (s == 'e') || (s == 'E') || 83 (s == 'i') || (s == 'I') || 84 (s == 'o') || (s == 'O') || 85 (s == 'u') || (s == 'U')) { 86 /* 87 * Append "way" to the word. 88 */ 89 (void) strcpy(cb, "way"); 90 } else { 91 /* 92 * Move first letter to the end 93 * of the word and add "ay". 94 */ 95 sb++; 96 *cb = s; 97 (void) strcpy(++cb, "ay"); 98 } 99 } else 100 *cb = '\0'; 101 102 /* 103 * Output the collected buffer, the last character 104 * read and reinitialize pointers for next round. 105 */ 106 (void) printf("%s", sb); 107 (void) putc(ic, stdout); 108 109 sb = cb = &buffer[0]; 110 word = ignore = 0; 111 112 continue; 113 } 114 115 /* 116 * Store this character into the word buffer. 117 */ 118 *cb++ = c; 119 *cb = '\0'; 120 word = 1; 121 } 122 123 return (0); 124 } 125