Searched refs:nRecordField (Results 1 – 1 of 1) sorted by relevance
233666 u16 nRecordField; /* Number of fields in aRecord[] */ member234686 while( pOld->nRecordField<nCol ){234690 int iField = pOld->nRecordField;234758 pNew->nRecordField++;234907 if( (*pp)->nRecordField!=pTab->nCol ){235211 pC->nRecordField = pTab->nCol;