Searched refs:aIDF (Results 1 – 1 of 1) sorted by relevance
244444 double *aIDF; /* IDF for each phrase */ member244493 p->aIDF = (double*)&p[1];244494 p->aFreq = &p->aIDF[nPhrase];244523 p->aIDF[i] = idf;244586 score += pData->aIDF[i] * (