Searched refs:rd1 (Results 1 – 5 of 5) sorted by relevance
/linux/Documentation/translations/zh_CN/scheduler/ |
H A D | sched-energy.rst | 92 RDs: |----rd1----|-----rd2-----| 95 每个根域包含6个CPU。这两个根域在上图中被表示为rd1和rd2。由于pd4与rd1和rd2 98 * rd1->pd: pd0 -> pd4
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/linux/net/wireless/ |
H A D | reg.c | 1336 static int reg_rules_intersect(const struct ieee80211_regdomain *rd1, in reg_rules_intersect() argument 1371 max_bandwidth1 = reg_get_max_bandwidth(rd1, rule1); in reg_rules_intersect() 1501 regdom_intersect(const struct ieee80211_regdomain *rd1, in regdom_intersect() argument 1511 if (!rd1 || !rd2) in regdom_intersect() 1522 for (x = 0; x < rd1->n_reg_rules; x++) { in regdom_intersect() 1523 rule1 = &rd1->reg_rules[x]; in regdom_intersect() 1526 if (!reg_rules_intersect(rd1, rd2, rule1, rule2, in regdom_intersect() 1539 for (x = 0; x < rd1->n_reg_rules; x++) { in regdom_intersect() 1540 rule1 = &rd1->reg_rules[x]; in regdom_intersect() 1543 r = reg_rules_intersect(rd1, rd2, rule1, rule2, in regdom_intersect() [all …]
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/linux/Documentation/scheduler/ |
H A D | sched-energy.rst | 104 RDs: |----rd1----|-----rd2-----| 108 containing 6 CPUs. The two root domains are denoted rd1 and rd2 in the 109 above figure. Since pd4 intersects with both rd1 and rd2, it will be 112 * rd1->pd: pd0 -> pd4
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/linux/Documentation/admin-guide/ |
H A D | md.rst | 604 So for a 3 drive array there will be rd0, rd1, rd2.
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/linux/Documentation/admin-guide/RAS/ |
H A D | main.rst | 1021 Ch1 phy rd1, wr1 (0x063f4031): 2 ranks, UDIMMs
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