Searched refs:breaker (Results 1 – 2 of 2) sorted by relevance
386 break_intermediate(struct roff_node *n, struct roff_node *breaker) in break_intermediate() argument388 if (n != breaker && in break_intermediate()392 while (n != breaker) { in break_intermediate()
972 addresses, with Rule 8 being a deterministic tie breaker.998 - Finally, run the check-all-bits (CommonPrefixLen) tie breaker.