Searched refs:adj0 (Results 1 – 1 of 1) sorted by relevance
330 double adj0, tol; local877 adj0 = dval(&adj) = 1.;880 adj0 = dval(&adj) *= 0.5;886 L = adj0;887 adj0 -= L;890 if (adj0 >= .5)894 if (asub && adj0 > 0.)898 if (!asub && adj0 > 0.) {972 dval(&adj) = adj0 - .5;974 if (adj0 > tol) {[all …]