Searched refs:aIDF (Results 1 – 1 of 1) sorted by relevance
245176 double *aIDF; /* IDF for each phrase */ member245225 p->aIDF = (double*)&p[1];245226 p->aFreq = &p->aIDF[nPhrase];245255 p->aIDF[i] = idf;245318 score += pData->aIDF[i] * (