35 	sxy = (hx ^ hy) & 0x80000000;  in remquo()
36 	sx = hx&0x80000000;		/* sign of x */  in remquo()
38 	hy &= 0x7fffffff;	/* |y| */  in remquo()
41 	if((hy|ly)==0||(hx>=0x7ff00000)||	/* y=0,or x not finite */  in remquo()
42 	  ((hy|((ly|-ly)>>31))>0x7ff00000))	/* or y is NaN */  in remquo()
46 		q = 0;  in remquo()
51 		return Zero[(u_int32_t)sx>>31];	/* |x|=|y| return x*0*/  in remquo()
56 	if(hx<0x00100000) {	/* subnormal x */  in remquo()
57 	    if(hx==0) {  in remquo()
58 		for (ix = -1043, i=lx; i>0; i<<=1) ix -=1;  in remquo()
60 		for (ix = -1022,i=(hx<<11); i>0; i<<=1) ix -=1;  in remquo()
65 	if(hy<0x00100000) {	/* subnormal y */  in remquo()
66 	    if(hy==0) {  in remquo()
67 		for (iy = -1043, i=ly; i>0; i<<=1) iy -=1;  in remquo()
69 		for (iy = -1022,i=(hy<<11); i>0; i<<=1) iy -=1;  in remquo()
75 	    hx = 0x00100000|(0x000fffff&hx);  in remquo()
83 		lx = 0;  in remquo()
87 	    hy = 0x00100000|(0x000fffff&hy);  in remquo()
95 		ly = 0;  in remquo()
101 	q = 0;  in remquo()
104 	    if(hz<0){hx = hx+hx+(lx>>31); lx = lx+lx;}  in remquo()
109 	if(hz>=0) {hx=hz;lx=lz;q++;}  in remquo()
112 	if((hx|lx)==0) {			/* return sign(x)*0 */  in remquo()
113 	    q &= 0x7fffffff;  in remquo()
117 	while(hx<0x00100000) {		/* normalize x */  in remquo()
122 	    hx = ((hx-0x00100000)|((iy+1023)<<20));  in remquo()
129 		lx = (hx<<(32-n))|(lx>>n); hx = 0;  in remquo()
131 		lx = hx>>(n-32); hx = 0;  in remquo()
137 	if (y < 0x1p-1021) {  in remquo()
148 	q &= 0x7fffffff;  in remquo()