Lines Matching full:year

13 	uint16_t year;		/* year (A.D.) */  member
14 	uint16_t yearday;	/* day of year, 1 = January 1 */
27 	uint16_t year;		/* year (A.D.) */  member
28 	uint8_t	 week;		/* 1..53, week in year */
83  * We deal in a 4 year cycle starting at March 1, 1900.	 We assume
91 #define	DAYSPERYEAR	(365)			/* days per year */
96 #define	SECSPERYEAR	(365 * SECSPERDAY)	/* regular year */
97 #define	SECSPERLEAPYEAR	(366 * SECSPERDAY)	/* leap year */
98 #define	SECSPERAVGYEAR	31556952		/* mean year length over 400yrs */
193  * Convert a number of elapsed month in a year into elapsed days
194  * in year.
199  * year. (Expect the resulting days to be negative, with a positive
200  * excess! But then, we need no leap year flag, either...)
220  * days in year.
222  * Note: This will give the true difference to the start of the given year,
229  * Convert the date part of a 'struct tm' (that is, year, month,
236  * Convert the date part of a 'struct calendar' (that is, year, month,
245  * number of elapsed days of that year in 'res.rem'.
257  * Given a number of elapsed days in a year and a leap year indicator,
267  * calendar'. Return 0 if the year is regular year, !0 if the year is
268  * a leap year.
275  * tm'. Return 0 if the year is regular year, !0 if the year is a leap
276  * year.
306  * convert a year number to rata die of year start
309 ntpcal_year_to_ystart(int32_t /* year */);
312  * For a given RataDie, get the RataDie of the associated year start,
322 ntpcal_rd_to_mstart(int32_t /* year */);
466  * Days in a normal 4 year leap year calendar cycle (1461).
471  * Days in a normal 100 year leap year calendar (36524).  We lose a
478  * The Gregorian calendar is based on a 400 year cycle. This is the
490  * Is a Greogorian calendar year a leap year? The obvious solution is to