/* * CDDL HEADER START * * The contents of this file are subject to the terms of the * Common Development and Distribution License (the "License"). * You may not use this file except in compliance with the License. * * You can obtain a copy of the license at usr/src/OPENSOLARIS.LICENSE * or http://www.opensolaris.org/os/licensing. * See the License for the specific language governing permissions * and limitations under the License. * * When distributing Covered Code, include this CDDL HEADER in each * file and include the License file at usr/src/OPENSOLARIS.LICENSE. * If applicable, add the following below this CDDL HEADER, with the * fields enclosed by brackets "[]" replaced with your own identifying * information: Portions Copyright [yyyy] [name of copyright owner] * * CDDL HEADER END */ /* * Copyright 2008 Sun Microsystems, Inc. All rights reserved. * Use is subject to license terms. */ #pragma ident "%Z%%M% %I% %E% SMI" .file "%M%" /* * Return the ptr in sptr at which the character c1 appears; * or NULL if not found in n chars; don't stop at \0. * void * * memchr(const void *sptr, int c1, size_t n) * { * if (n != 0) { * unsigned char c = (unsigned char)c1; * const unsigned char *sp = sptr; * * do { * if (*sp++ == c) * return ((void *)--sp); * } while (--n != 0); * } * return (NULL); * } */ #include ! The first part of this algorithm focuses on determining ! whether or not the desired character is in the first few bytes ! of memory, aligning the memory for word-wise copies, and ! initializing registers to detect zero bytes ENTRY(memchr) .align 32 tst %o2 ! n == 0 ? bz .notfound ! yup, c not found, return null ptr andcc %o0, 3, %o4 ! s word aligned ? add %o0, %o2, %o0 ! s + n sub %g0, %o2, %o2 ! n = -n bz .prepword ! yup, prepare for word-wise search and %o1, 0xff, %o1 ! search only for this one byte ldub [%o0 + %o2], %o3 ! s[0] cmp %o3, %o1 ! s[0] == c ? be .done ! yup, done nop ! addcc %o2, 1, %o2 ! n++, s++ bz .notfound ! c not found in first n bytes cmp %o4, 3 ! only one byte needed to align? bz .prepword2 ! yup, prepare for word-wise search sll %o1, 8, %g1 ! start spreading c across word ldub [%o0 + %o2], %o3 ! s[1] cmp %o3, %o1 ! s[1] == c ? be .done ! yup, done nop ! addcc %o2, 1, %o2 ! n++, s++ bz .notfound ! c not found in first n bytes cmp %o4, 2 ! only two bytes needed to align? bz .prepword3 ! yup, prepare for word-wise search sethi %hi(0x01010101), %o4 ! start loading Alan Mycroft's magic1 ldub [%o0 + %o2], %o3 ! s[1] cmp %o3, %o1 ! s[1] == c ? be .done ! yup, done nop addcc %o2, 1, %o2 ! n++, s++ bz .notfound ! c not found in first n bytes nop .prepword: sll %o1, 8, %g1 ! spread c -------------+ .prepword2: ! ! sethi %hi(0x01010101), %o4 ! Alan Mycroft's magic1 ! .prepword3: ! ! or %o1, %g1, %o1 ! across all <---------+ or %o4, %lo(0x01010101),%o4! finish loading magic1 ! sll %o1, 16, %g1 ! four bytes <--------+ sll %o4, 7, %o5 ! Alan Mycroft's magic2 ! or %o1, %g1, %o1 ! of a word <--------+ .searchchar: lduw [%o0 + %o2], %o3 ! src word .searchchar2: addcc %o2, 4, %o2 ! s+=4, n+=4 bcs .lastword ! if counter wraps, last word xor %o3, %o1, %g1 ! tword = word ^ c andn %o5, %g1, %o3 ! ~tword & 0x80808080 sub %g1, %o4, %g1 ! (tword - 0x01010101) andcc %o3, %g1, %g0 ! ((tword - 0x01010101) & ~tword & 0x80808080) bz,a .searchchar2 ! c not found if magic expression == 0 lduw [%o0 + %o2], %o3 ! src word ! here we know "word" contains the searched character, and no byte in ! "word" exceeds n. If we had exceeded n, we would have gone to label ! .lastword. "tword" has null bytes where "word" had c. After ! restoring "tword" from "(tword - 0x01010101)" in %g1, examine "tword" .foundchar: add %g1, %o4, %g1 ! restore tword set 0xff000000, %o4 ! mask for 1st byte andcc %g1, %o4, %g0 ! first byte zero (= found c) ? bz,a .done ! yup, done sub %o2, 4, %o2 ! n -= 4 (undo counter bumping) set 0x00ff0000, %o5 ! mask for 2nd byte andcc %g1, %o5, %g0 ! second byte zero (= found c) ? bz,a .done ! yup, done sub %o2, 3, %o2 ! n -= 3 (undo counter bumping) srl %o4, 16, %o4 ! 0x0000ff00 = mask for 3rd byte andcc %g1, %o4, %g0 ! third byte zero (= found c) ? bz,a .done ! nope, must be fourth byte sub %o2, 2, %o2 ! n -= 2 (undo counter bumping) sub %o2, 1, %o2 ! n -= 1, if fourth byte retl ! done with leaf function add %o0, %o2, %o0 ! return pointer to c in s .done: retl ! done with leaf function add %o0, %o2, %o0 ! return pointer to c in s nop nop ! Here we know that "word" is the last word in the search, and that ! some bytes possibly exceed n. However, "word" might also contain c. ! "tword" (in %g1) has null bytes where "word" had c. Examine "tword" ! while keeping track of number of remaining bytes .lastword: set 0xff000000, %o4 ! mask for 1st byte sub %o2, 4, %o2 ! n -= 4 (undo counter bumping) andcc %g1, %o4, %g0 ! first byte zero (= found c) ? bz .done ! yup, done set 0x00ff0000, %o5 ! mask for 2nd byte addcc %o2, 1, %o2 ! n += 1 bz .notfound ! c not found in first n bytes andcc %g1, %o5, %g0 ! second byte zero (= found c) ? bz .done ! yup, done srl %o4, 16, %o4 ! 0x0000ff00 = mask for 3rd byte addcc %o2, 1, %o2 ! n += 1 bz .notfound ! c not found in first n bytes andcc %g1, %o4, %g0 ! third byte zero (= found c) ? bz .done ! yup, done nop ! addcc %o2, 1, %o2 ! n += 1 bz .notfound ! c not found in first n bytes andcc %g1, 0xff, %g0 ! fourth byte zero (= found c) ? bz .done ! yup, done nop .notfound: retl ! done with leaf function mov %g0, %o0 ! return null pointer SET_SIZE(memchr)